Prime Dates
HackerRank 问题: Prime Dates
Categories:
Question
Given two dates each in the format dd-mm-yyyy, you have to find the number of lucky dates between them (inclusive). To see if a date is lucky,
- Firstly, sequentially concatinate the date, month and year, into a new integer
x
erasing the leading zeroes. - Now if
x
is divisible by either4
or7
, then we call the date a lucky date.
For example, let’s take the date “02-08-2024”. After concatinating the day, month and year, we get x
= 2082024. As x
is divisible by 4
so the date “02-08-2024” is called a lucky date.
Debug the given function findPrimeDates and/or other lines of code, to find the correct lucky dates from the given input.
Note: You can modify at most five lines in the given code and you cannot add or remove lines to the code.
Answer
import re
month = []
def updateLeapYear(year):
if year % 400 == 0:
# 1. leap year wrong, change 28 => 29
month[2] = 29
elif year % 100 == 0:
# 2. leap year wrong, change 29 => 28
month[2] = 28
elif year % 4 == 0:
month[2] = 29
else:
month[2] = 28
def storeMonth():
month[1] = 31
month[2] = 28
month[3] = 31
month[4] = 30
month[5] = 31
month[6] = 30
month[7] = 31
month[8] = 31
month[9] = 30
month[10] = 31
month[11] = 30
month[12] = 31
def findPrimeDates(d1, m1, y1, d2, m2, y2):
storeMonth()
result = 0
while(True):
x = d1
x = x * 100 + m1
# 3: 1000 -> 10000
x = x * 10000 + y1
# 4: condition wrong, change "and" to "or"
if x % 4 == 0 or x % 7 == 0:
result = result + 1
if d1 == d2 and m1 == m2 and y1 == y2:
break
updateLeapYear(y1)
d1 = d1 + 1
if d1 > month[m1]:
m1 = m1 + 1
d1 = 1
if m1 > 12:
y1 = y1 + 1
# 5: month reset
m1 = 1
for i in range(1, 15):
month.append(31)
line = input()
date = re.split('-| ', line)
d1 = int(date[0])
m1 = int(date[1])
y1 = int(date[2])
d2 = int(date[3])
m2 = int(date[4])
y2 = int(date[5])
result = findPrimeDates(d1, m1, y1, d2, m2, y2)
print(result)